Support new xml binary format

This commit is contained in:
topjohnwu 2017-10-31 22:48:48 +08:00
parent fdd700f3e5
commit 5f22d3e055

View File

@ -43,13 +43,12 @@ public class HideManager extends ParallelTask<Void, Void, Boolean> {
return builder.toString(); return builder.toString();
} }
private boolean findAndPatch(byte xml[], String from, String to) { private int findOffset(byte buf[], byte pattern[]) {
int offset = -1; int offset = -1;
byte target[] = (from + '\0').getBytes(); for (int i = 0; i < buf.length - pattern.length; ++i) {
for (int i = 0; i < xml.length - target.length; ++i) {
boolean match = true; boolean match = true;
for (int j = 0; j < target.length; ++j) { for (int j = 0; j < pattern.length; ++j) {
if (xml[i + j] != target[j]) { if (buf[i + j] != pattern[j]) {
match = false; match = false;
break; break;
} }
@ -59,9 +58,32 @@ public class HideManager extends ParallelTask<Void, Void, Boolean> {
break; break;
} }
} }
return offset;
}
/* It seems that AAPT sometimes generate another type of string format */
private boolean fallbackPatch(byte xml[], String from, String to) {
byte[] target = new byte[from.length() * 2 + 2];
for (int i = 0; i < from.length(); ++i) {
target[i * 2] = (byte) from.charAt(i);
}
int offset = findOffset(xml, target);
if (offset < 0) if (offset < 0)
return false; return false;
byte[] dest = new byte[target.length - 2];
for (int i = 0; i < to.length(); ++i) {
dest[i * 2] = (byte) to.charAt(i);
}
System.arraycopy(dest, 0, xml, offset, dest.length);
return true;
}
private boolean findAndPatch(byte xml[], String from, String to) {
byte target[] = (from + '\0').getBytes();
int offset = findOffset(xml, target);
if (offset < 0)
return fallbackPatch(xml, from, to);
System.arraycopy(to.getBytes(), 0, xml, offset, to.length()); System.arraycopy(to.getBytes(), 0, xml, offset, to.length());
return true; return true;
} }