tailscale/util/rands/cheap.go
Maisem Ali 36e8e8cd64 wgengine/magicsock: use math/rands/v2
Updates #11058

Co-authored-by: James Tucker <james@tailscale.com>
Signed-off-by: Maisem Ali <maisem@tailscale.com>
2024-06-05 15:57:27 -07:00

91 lines
2.9 KiB
Go

// Copyright (c) Tailscale Inc & AUTHORS
// SPDX-License-Identifier: BSD-3-Clause
// Copyright 2009 The Go Authors. All rights reserved.
// Use of this source code is governed by a BSD-style
// license that can be found in the LICENSE file.
package rands
import (
"math/bits"
randv2 "math/rand/v2"
)
// Shuffle is like rand.Shuffle, but it does not allocate or lock any RNG state.
func Shuffle[T any](seed uint64, data []T) {
var pcg randv2.PCG
pcg.Seed(seed, seed)
for i := len(data) - 1; i > 0; i-- {
j := int(uint64n(&pcg, uint64(i+1)))
data[i], data[j] = data[j], data[i]
}
}
// IntN is like rand.IntN, but it is seeded on the stack and does not allocate
// or lock any RNG state.
func IntN(seed uint64, n int) int {
var pcg randv2.PCG
pcg.Seed(seed, seed)
return int(uint64n(&pcg, uint64(n)))
}
// Perm is like rand.Perm, but it is seeded on the stack and does not allocate
// or lock any RNG state.
func Perm(seed uint64, n int) []int {
p := make([]int, n)
for i := range p {
p[i] = i
}
Shuffle(seed, p)
return p
}
// uint64n is the no-bounds-checks version of rand.Uint64N from the standard
// library. 32-bit optimizations have been elided.
func uint64n(pcg *randv2.PCG, n uint64) uint64 {
if n&(n-1) == 0 { // n is power of two, can mask
return pcg.Uint64() & (n - 1)
}
// Suppose we have a uint64 x uniform in the range [0,2⁶⁴)
// and want to reduce it to the range [0,n) preserving exact uniformity.
// We can simulate a scaling arbitrary precision x * (n/2⁶⁴) by
// the high bits of a double-width multiply of x*n, meaning (x*n)/2⁶⁴.
// Since there are 2⁶⁴ possible inputs x and only n possible outputs,
// the output is necessarily biased if n does not divide 2⁶⁴.
// In general (x*n)/2⁶⁴ = k for x*n in [k*2⁶⁴,(k+1)*2⁶⁴).
// There are either floor(2⁶⁴/n) or ceil(2⁶⁴/n) possible products
// in that range, depending on k.
// But suppose we reject the sample and try again when
// x*n is in [k*2⁶⁴, k*2⁶⁴+(2⁶⁴%n)), meaning rejecting fewer than n possible
// outcomes out of the 2⁶⁴.
// Now there are exactly floor(2⁶⁴/n) possible ways to produce
// each output value k, so we've restored uniformity.
// To get valid uint64 math, 2⁶⁴ % n = (2⁶⁴ - n) % n = -n % n,
// so the direct implementation of this algorithm would be:
//
// hi, lo := bits.Mul64(r.Uint64(), n)
// thresh := -n % n
// for lo < thresh {
// hi, lo = bits.Mul64(r.Uint64(), n)
// }
//
// That still leaves an expensive 64-bit division that we would rather avoid.
// We know that thresh < n, and n is usually much less than 2⁶⁴, so we can
// avoid the last four lines unless lo < n.
//
// See also:
// https://lemire.me/blog/2016/06/27/a-fast-alternative-to-the-modulo-reduction
// https://lemire.me/blog/2016/06/30/fast-random-shuffling
hi, lo := bits.Mul64(pcg.Uint64(), n)
if lo < n {
thresh := -n % n
for lo < thresh {
hi, lo = bits.Mul64(pcg.Uint64(), n)
}
}
return hi
}