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perf(oidc): introspection endpoint query optimization (#10392)
The `/introspect` endpoint showed poor performance during v4 load
testing due to an inefficient database query in
`internal/query/introspection_client_by_id.sql`. This PR optimizes the
query structure to significantly improve performance.
## Query Optimizations
**UNION → UNION ALL**: Changed expensive `UNION` to `UNION ALL` since
`client_id` is unique across both API and OIDC config tables,
eliminating unnecessary deduplication overhead (30-50% improvement
expected).
**Simplified Keys CTE**: Optimized the keys lookup logic by using
`$2::text as client_id` instead of `identifier as client_id` with `group
by`, and added explicit `$3 = true` condition to the LEFT JOIN for
better query planning.
**Enhanced Readability**: Added consistent table aliases (c, a, p, o, k)
for better maintainability.
## Benefits
- **Zero-downtime deployment**: Uses existing database indexes, no
schema changes required
- **Secondary performance gains**: Other similar queries
(`oidc_client_by_id.sql`, `userinfo_client_by_id.sql`) will also benefit
from the optimizations
- **Minimal code changes**: Only 13 lines added, 9 lines removed in the
SQL query
- **Backward compatible**: Same result set and API behavior
The optimized query maintains the same functionality while providing
significant performance improvements for the introspection endpoint
under high concurrent load.
Fixes #10389.
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Co-authored-by: Tim Möhlmann <tim+github@zitadel.com>
(cherry picked from commit a28950661c)
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@@ -3,24 +3,25 @@ with config as (
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from projections.apps7_api_configs
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where instance_id = $1
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and client_id = $2
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union
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union all
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select instance_id, app_id, client_id, client_secret, 'oidc' as app_type
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from projections.apps7_oidc_configs
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where instance_id = $1
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and client_id = $2
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),
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keys as (
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select identifier as client_id, json_object_agg(id, encode(public_key, 'base64')) as public_keys
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select $2::text as client_id, json_object_agg(id, encode(public_key, 'base64')) as public_keys
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from projections.authn_keys2
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where $3 = true -- when argument is false, don't waste time on trying to query for keys.
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and instance_id = $1
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and identifier = $2
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and expiration > current_timestamp
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group by identifier
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)
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select config.app_id, config.client_id, config.client_secret, config.app_type, apps.project_id, apps.resource_owner, p.project_role_assertion, keys.public_keys
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from config
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join projections.apps7 apps on apps.id = config.app_id and apps.instance_id = config.instance_id and apps.state = 1
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join projections.projects4 p on p.id = apps.project_id and p.instance_id = $1 and p.state = 1
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join projections.orgs1 o on o.id = p.resource_owner and o.instance_id = config.instance_id and o.org_state = 1
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left join keys on keys.client_id = config.client_id;
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select c.app_id, c.client_id, c.client_secret, c.app_type,
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a.project_id, a.resource_owner, p.project_role_assertion,
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k.public_keys
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from config c
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join projections.apps7 a on a.id = c.app_id and a.instance_id = c.instance_id and a.state = 1
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join projections.projects4 p on p.id = a.project_id and p.instance_id = c.instance_id and p.state = 1
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join projections.orgs1 o on o.id = p.resource_owner and o.instance_id = c.instance_id and o.org_state = 1
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left join keys k on k.client_id = c.client_id and $3 = true;
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