TheArchive/headscale
1
0
Fork 0
mirror of https://github.com/juanfont/headscale.git synced 2024-12-28 02:37:50 +00:00
Code Issues Packages Projects Releases Wiki Activity

Merge branch 'main' into remove-shared

Browse Source
This commit is contained in:
Kristoffer Dalby 2022-02-22 16:48:14 +00:00 committed by GitHub
commit ec58979ce0
No known key found for this signature in database
GPG Key ID: 4AEE18F83AFDEB23
1 changed files with 0 additions and 15 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

15
machine.go
View File

@ -166,21 +166,6 @@ func getFilteredByACLPeers(
peers := make(map[uint64]Machine)
// Aclfilter peers here. We are itering through machines in all namespaces and search through the computed aclRules
// for match between rule SrcIPs and DstPorts. If the rule is a match we allow the machine to be viewable.
// FIXME: On official control plane if a rule allow user A to talk to user B but NO rule allows user B to talk to
// user A. The behaviour is the following
//
// On official tailscale control plane:
// on first `tailscale status`` on node A we can see node B. The `tailscale status` command on node B doesn't show node A
// We can successfully establish a communication from A to B. When it's done, if we run the `tailscale status` command
// on node B again we can now see node A. It's not possible to establish a communication from node B to node A.
// On this implementation of the feature
// on any `tailscale status` command on node A we can see node B. The `tailscale status` command on node B DOES show A.
//
// I couldn't find a way to not clutter the output of `tailscale status` with all nodes that we could be talking to.
// In order to do this we would need to be able to identify that node A want to talk to node B but that Node B doesn't know
// how to talk to node A and then add the peering resource.
for _, peer := range machines {
if peer.ID == machine.ID {
continue