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util/sha256x: make Hash.Sum non-escaping (#5338)
Since Hash is a concrete type, we can make it such that Sum never escapes the input. Signed-off-by: Joe Tsai <joetsai@digital-static.net>
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@ -45,10 +45,19 @@ func (h *Hash) Sum(b []byte) []byte {
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h.h.Write(h.x[:h.nx])
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h.nx = 0
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}
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return h.h.Sum(b)
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// Unfortunately hash.Hash.Sum always causes the input to escape since
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// escape analysis cannot prove anything past an interface method call.
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// Assuming h already escapes, we call Sum with h.x first,
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// and then the copy the result to b.
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sum := h.h.Sum(h.x[:0])
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return append(b, sum...)
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}
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func (h *Hash) Reset() {
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if h.h == nil {
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h.h = sha256.New()
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}
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h.h.Reset()
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h.nx = 0
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}
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@ -64,6 +64,7 @@ func hashSuite(h hasher) {
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h.HashBytes(bytes[:(i+1)*13])
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}
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}
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func Test(t *testing.T) {
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c := qt.New(t)
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h1 := New()
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@ -73,6 +74,16 @@ func Test(t *testing.T) {
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c.Assert(h1.Sum(nil), qt.DeepEquals, h2.Sum(nil))
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}
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func TestSumAllocations(t *testing.T) {
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c := qt.New(t)
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h := New()
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n := testing.AllocsPerRun(100, func() {
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var a [sha256.Size]byte
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h.Sum(a[:0])
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})
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c.Assert(n, qt.Equals, 0.0)
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}
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func Fuzz(f *testing.F) {
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f.Fuzz(func(t *testing.T, seed int64) {
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c := qt.New(t)
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